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transformation: default no formulae given

refactoring
Sebastian Junges 6 years ago
parent
commit
7bb7023e01
  1. 4
      src/core/transformation.cpp

4
src/core/transformation.cpp

@ -3,6 +3,6 @@
void define_transformation(py::module& m) { void define_transformation(py::module& m) {
// Transform model // Transform model
m.def("_transform_to_sparse_model", &storm::api::transformSymbolicToSparseModel<storm::dd::DdType::Sylvan, double>, "Transform symbolic model into sparse model", py::arg("model"), py::arg("formulae"));
m.def("_transform_to_sparse_parametric_model", &storm::api::transformSymbolicToSparseModel<storm::dd::DdType::Sylvan, storm::RationalFunction>, "Transform symbolic parametric model into sparse parametric model", py::arg("model"), py::arg("formulae"));
m.def("_transform_to_sparse_model", &storm::api::transformSymbolicToSparseModel<storm::dd::DdType::Sylvan, double>, "Transform symbolic model into sparse model", py::arg("model"), py::arg("formulae") = std::vector<std::shared_ptr<storm::logic::Formula const>>());
m.def("_transform_to_sparse_parametric_model", &storm::api::transformSymbolicToSparseModel<storm::dd::DdType::Sylvan, storm::RationalFunction>, "Transform symbolic parametric model into sparse parametric model", py::arg("model"), py::arg("formulae") = std::vector<std::shared_ptr<storm::logic::Formula const>>());
} }
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