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							62 lines
						
					
					
						
							1.9 KiB
						
					
					
				| /* MFASP, Minimum Feedback Arc Set Problem */ | |
| 
 | |
| /* Written in GNU MathProg by Andrew Makhorin <mao@gnu.org> */ | |
| 
 | |
| /* The Minimum Feedback Arc Set Problem for a given directed graph | |
|    G = (V, E), where V is a set of vertices and E is a set of arcs, is | |
|    to find a minimal subset of arcs, which being removed from the graph | |
|    make it acyclic. | |
|  | |
|    Reference: | |
|    Garey, M.R., and Johnson, D.S. (1979), Computers and Intractability: | |
|    A guide to the theory of NP-completeness [Graph Theory, Covering and | |
|    Partitioning, Minimum Feedback Arc Set, GT9]. */ | |
| 
 | |
| param n, integer, >= 0; | |
| /* number of vertices */ | |
| 
 | |
| set V, default 1..n; | |
| /* set of vertices */ | |
| 
 | |
| set E, within V cross V, | |
| default setof{i in V, j in V: i <> j and Uniform(0,1) <= 0.15} (i,j); | |
| /* set of arcs */ | |
| 
 | |
| printf "Graph has %d vertices and %d arcs\n", card(V), card(E); | |
| 
 | |
| var x{(i,j) in E}, binary; | |
| /* x[i,j] = 1 means that (i->j) is a feedback arc */ | |
| 
 | |
| /* It is known that a digraph G = (V, E) is acyclic if and only if its | |
|    vertices can be assigned numbers from 1 to |V| in such a way that | |
|    k[i] + 1 <= k[j] for every arc (i->j) in E, where k[i] is a number | |
|    assigned to vertex i. We may use this condition to require that the | |
|    digraph G = (V, E \ E'), where E' is a subset of feedback arcs, is | |
|    acyclic. */ | |
| 
 | |
| var k{i in V}, >= 1, <= card(V); | |
| /* k[i] is a number assigned to vertex i */ | |
| 
 | |
| s.t. r{(i,j) in E}: k[j] - k[i] >= 1 - card(V) * x[i,j]; | |
| /* note that x[i,j] = 1 leads to a redundant constraint */ | |
| 
 | |
| minimize obj: sum{(i,j) in E} x[i,j]; | |
| /* the objective is to minimize the cardinality of a subset of feedback | |
|    arcs */ | |
| 
 | |
| solve; | |
| 
 | |
| printf "Minimum feedback arc set:\n"; | |
| printf{(i,j) in E: x[i,j]} "%d %d\n", i, j; | |
| 
 | |
| data; | |
| 
 | |
| /* The optimal solution is 3 */ | |
| 
 | |
| param n := 15; | |
| 
 | |
| set E := 1 2, 2 3, 3 4, 3 8, 4 9, 5 1, 6 5, 7 5, 8 6, 8 7, 8 9, 9 10, | |
|          10 11, 10 14, 11 15, 12 7, 12 8, 12 13, 13 8, 13 12, 13 14, | |
|          14 9, 15 14; | |
| 
 | |
| end;
 |