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added magic square ex2

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Stefan Pranger 2 years ago
parent
commit
776aeca333
  1. BIN
      ex2/practical_assignment2.pdf
  2. 67
      ex2/square.py
  3. 3
      ex2/test0.txt
  4. 4
      ex2/test1.txt

BIN
ex2/practical_assignment2.pdf

67
ex2/square.py

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# coding: utf-8
import os, sys
from z3 import *
# get the playground information
if len(sys.argv) != 2:
print("Usage: python3 square.py <level-file>")
sys.exit(0)
with open(sys.argv[1]) as f:
playground = f.read()
rows = playground.strip().split("\n")
playground = [[None if x == "_" else int(x) for x in r.split()] for r in rows]
# get the playground size
size_y = len(playground)
assert(size_y != 0)
size_x = len(playground[0])
assert(size_x != 0)
assert(size_x == size_y)
#################################### Square ####################################
# create the solver
solver = Solver()
# todo: create an integer variable for each playground cell
# hint: use something like the coordinates as part of the variable name
numbers = [[None for _j in range(size_x)] for _j in range(size_y)]
for i in range(size_y):
for j in range(size_x):
pass # ... replace this with your code ...
# todo: assign each known number the corresponding value from playground
for i in range(size_y):
for j in range(size_x):
pass # ... replace this with your code ...
# todo: declare a variable for the sum of all columns, rows and diagonals
# ... your code goes here ...
# todo: enforce that each column sums up to the declared variable
for j in range(size_x):
pass # ... replace this with your code ...
# todo: enforce that each row sums up to the declared variable
for i in range(size_y):
pass # ... replace this with your code ...
# todo: enforce that both diagonals sum up to the declared variable
# call the solver and check satisfiability
res = solver.check()
if res != sat:
print("unsat")
sys.exit(1)
# print the model
m = solver.model()
for i in range(size_y):
results = []
for j in range(size_x):
num = numbers[i][j]
results.append("_" if num is None else m[num].as_long())
print(("%4s" * len(results)) % tuple(results))
################################################################################

3
ex2/test0.txt

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_ _ 28
_ 35 21
_ 7 _

4
ex2/test1.txt

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_ _ 28 _
_ 35 21 _
_ 7 _ _
_ _ _ _
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