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// Compute and print the n-th Fibonacci number.
// We work with integers and real numbers.
#include <cln/integer.h>
#include <cln/real.h>
// We do I/O.
#include <cln/io.h>
#include <cln/integer_io.h>
// We use the timing functions.
#include <cln/timing.h>
using namespace std; using namespace cln;
// F_n is defined through the recurrence relation
// F_0 = 0, F_1 = 1, F_(n+2) = F_(n+1) + F_n.
// The following addition formula holds:
// F_(n+m) = F_(m-1) * F_n + F_m * F_(n+1) for m >= 1, n >= 0.
// (Proof: For fixed m, the LHS and the RHS satisfy the same recurrence
// w.r.t. n, and the initial values (n=0, n=1) agree. Hence all values agree.)
// Replace m by m+1:
// F_(n+m+1) = F_m * F_n + F_(m+1) * F_(n+1) for m >= 0, n >= 0
// Now put in m = n, to get
// F_(2n) = (F_(n+1)-F_n) * F_n + F_n * F_(n+1) = F_n * (2*F_(n+1) - F_n)
// F_(2n+1) = F_n ^ 2 + F_(n+1) ^ 2
// hence
// F_(2n+2) = F_(n+1) * (2*F_n + F_(n+1))
struct twofibs { cl_I u; // F_n
cl_I v; // F_(n+1)
// Constructor.
twofibs (const cl_I& uu, const cl_I& vv) : u (uu), v (vv) {} };
// Returns F_n and F_(n+1). Assume n>=0.
static const twofibs fibonacci2 (int n) { if (n==0) return twofibs(0,1); int m = n/2; // floor(n/2)
twofibs Fm = fibonacci2(m); // Since a squaring is cheaper than a multiplication, better use
// three squarings instead of one multiplication and two squarings.
cl_I u2 = square(Fm.u); cl_I v2 = square(Fm.v); if (n==2*m) { // n = 2*m
cl_I uv2 = square(Fm.v - Fm.u); return twofibs(v2 - uv2, u2 + v2); } else { // n = 2*m+1
cl_I uv2 = square(Fm.u + Fm.v); return twofibs(u2 + v2, uv2 - u2); } }
// Returns just F_n. Assume n>=0.
const cl_I fibonacci (int n) { if (n==0) return 0; int m = n/2; // floor(n/2)
twofibs Fm = fibonacci2(m); if (n==2*m) { // n = 2*m
// Here we don't use the squaring formula because
// one multiplication is cheaper than two squarings.
cl_I& u = Fm.u; cl_I& v = Fm.v; return u * ((v << 1) - u); } else { // n = 2*m+1
cl_I u2 = square(Fm.u); cl_I v2 = square(Fm.v); return u2 + v2; } }
// The next routine is a variation of the above. It is mathematically
// equivalent but implemented in a non-recursive way.
const cl_I fibonacci_compact (int n) { if (n==0) return 0; cl_I u = 0; cl_I v = 1; cl_I m = n/2; // floor(n/2)
for (uintC bit=integer_length(m); bit>0; --bit) { // Since a squaring is cheaper than a multiplication, better use
// three squarings instead of one multiplication and two squarings.
cl_I u2 = square(u); cl_I v2 = square(v); if (logbitp(bit-1, m)) { v = square(u + v) - u2; u = u2 + v2; } else { u = v2 - square(v - u); v = u2 + v2; } } if (n==2*m) // Here we don't use the squaring formula because
// one multiplication is cheaper than two squarings.
return u * ((v << 1) - u); else return square(u) + square(v); }
// Returns just F_n, computed as the nearest integer to
// ((1+sqrt(5))/2)^n/sqrt(5). Assume n>=0.
const cl_I fibonacci_slow (int n) { // Need a precision of ((1+sqrt(5))/2)^-n.
float_format_t prec = float_format((int)(0.208987641*n+5)); cl_R sqrt5 = sqrt(cl_float(5,prec)); cl_R phi = (1+sqrt5)/2; return round1( expt(phi,n)/sqrt5 ); }
#ifndef TIMING
int main (int argc, char* argv[]) { if (argc != 2) { cerr << "Usage: fibonacci n" << endl; return(1); } int n = atoi(argv[1]); cout << "fib(" << n << ") = " << fibonacci(n) << endl; return(0); }
#else // TIMING
int main (int argc, char* argv[]) { int repetitions = 100; if ((argc >= 3) && !strcmp(argv[1],"-r")) { repetitions = atoi(argv[2]); argc -= 2; argv += 2; } if (argc != 2) { cerr << "Usage: fibonacci n" << endl; return(1); } int n = atoi(argv[1]); { CL_TIMING; cout << "fib(" << n << ") = "; for (int rep = repetitions-1; rep > 0; rep--) fibonacci(n); cout << fibonacci(n) << endl; } { CL_TIMING; cout << "fib(" << n << ") = "; for (int rep = repetitions-1; rep > 0; rep--) fibonacci_compact(n); cout << fibonacci_compact(n) << endl; } { CL_TIMING; cout << "fib(" << n << ") = "; for (int rep = repetitions-1; rep > 0; rep--) fibonacci_slow(n); cout << fibonacci_slow(n) << endl; } return(0); }
#endif
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