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34 lines
1.5 KiB
34 lines
1.5 KiB
\item \self Compute the propositional formula of the following circuit.
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\tikzstyle{branch}=[fill,shape=circle,minimum size=3pt,inner sep=0pt]
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\begin{tikzpicture}[label distance=2mm]
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\node (a) at (0,0) {$a$};
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\node (b) at (0,-1) {$b$};
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\node (c) at (0,-2) {$c$};
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\node (z) at (8,-1) {$z$};
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\node (bm) at (3,-1) {};
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\node (cm1) at (2,-2) {};
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\node (cm2) at (3,-2) {};
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\node (bc_c1) at (2,-1.1) {};
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\node (bc_c2) at (2.1,-1) {};
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\node (bc_c3) at (2,-.9) {};
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\node (not1m) at (3,0) {};
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\node (and1m) at (5,-.5) {};
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\node (nand1m) at (5,-1.5) {};
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\node[not gate US, draw, logic gate inputs=n] at ($(2,0)$) (not1) {\tiny NOT};
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\node[and gate US, draw, logic gate inputs=nn] at ($(4,-.5)$) (and1) {\tiny AND};
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\node[nand gate US, draw, logic gate inputs=nn] at ($(4,-1.5)$) (nand1) {\tiny NAND};
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\node[xor gate US, draw, logic gate inputs=nn] at ($(6,-1)$) (xor1) {\tiny XOR};
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\draw (a.east) -- (not1.input);
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\draw (not1.output) -| (not1m.center) node[above] {$w$} |- (and1.input 1);
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\draw (c.east) -| (cm1.center) node[circle, fill,inner sep=2pt] {} -- (bc_c1.center) -- (bc_c2.center) -- (bc_c3.center) |- (and1.input 2);
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\draw (b.east) -| (bm.center) |- (nand1.input 1);
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\draw (c.east) -| (cm2.center) |- (nand1.input 2);
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\draw (and1.output) -| (and1m.center) node[above] {$x$} |- (xor1.input 1);
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\draw (nand1.output) -| (nand1m.center) node[below] {$y$} |- (xor1.input 2);
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\draw (xor1.output) -- (z);
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\end{tikzpicture}
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