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This sequent is provable.
\begin{logicproof}{2}
(s \lor \lnot u) \imp t & \prem \\
s \lor \lnot s & $\LEM$ \\
\begin{subproof}
s & \assum \\
s\lor \lnot u & $\ori{1} 3$ \\
t & $\impe 4, 1$ \\
(\lnot s \land u) \lor t & $\ori{2} 5$
\end{subproof}
\begin{subproof}
\lnot s & \assum \\
u \lor \lnot u & $\LEM$ \\
\begin{subproof}
u & \assum \\
\lnot s \land u & $\andi 7,9$ \\
(\lnot s\land u) \lor t & $\ori{1} 10$
\end{subproof}
\begin{subproof}
\lnot u & \assum \\
s \lor \lnot u & $\ori{2} 12$ \\
t & $\impe 13 1$ \\
(\lnot s\land u) \lor t & $\ori{2} 14$
\end{subproof}
(\lnot s\land u) \lor t & $\ore 8, 9-11, 12-15$
\end{subproof}
(\lnot s\land u) \lor t & $\ore 2, 3-6, 7-16$
\end{logicproof}