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This sequent is provable.
\begin{logicproof}{3}
\begin{subproof}
\neg ((p \imp q) \lor \neg q) & \assum\\
\begin{subproof}
p \imp q & \assum \\
(p \imp q) \lor \neg q & $\ori{1} 3$ \\
\bot & $\nege 3, 1 $
\end{subproof}
\neg (p \imp q) & $\negi 2-4 $ \\
\begin{subproof}
q & \assum \\
\begin{subproof}
p & \assum \\
q & $\copying 6$
\end{subproof}
p \imp q & $\impi 7-8$ \\
\bot & $\nege 9, 5$
\end{subproof}
\neg q & $\negi 6-10$ \\
(p \imp q) \lor \neg q & $\ori 11$ \\
\bot & $\nege 12, 1$
\end{subproof}
(p \imp q) \lor \neg q & $\PBC 1-13$
\end{logicproof}