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This sequent is provable.
\begin{logicproof}{2}
\lnot (a \lor b) & prem. \\
a \lor \lnot a & LEM \\
\begin{subproof}
a & ass. \\
a \lor b & $\lor$i1 3 \\
\bot & $\lnot$e 4,1 \\
\lnot a \land \lnot b & $\bot$e 5
\end{subproof}
\begin{subproof}
\lnot a & ass. \\
\begin{subproof}
b & ass. \\
a \lor b & $\lor$i2 8 \\
\bot & $\lnot$e 9,1
\end{subproof}
\lnot b & $\lnot$i 8-10 \\
\lnot a \land \lnot b & $\land$i 7, 11
\end{subproof}
\lnot a \land \lnot b & $\lor$e 2, 3-6, 7-12
\end{logicproof}
Alternate solution:
\begin{logicproof}{2}
\lnot(a \lor b) & prem \\
\begin{subproof}
a & ass \\
a \lor b & $\lor\mathrm{i}_1$ 2 \\
\bot & $\lnot$e 1,3
\end{subproof}
\lnot a & $\lnot$i 2--4 \\
\begin{subproof}
b & ass \\
a \lor b & $\lor\mathrm{i}_2$ 6 \\
\bot & $\lnot$e 1,7
\end{subproof}
\lnot b & $\lnot$i 6--8 \\
\lnot a \land \lnot b & $\land$i 5,9
\end{logicproof}