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\item \self Consider the following conflict graph with the following set of clauses:
\begin{tikzpicture}[->,>=stealth',shorten >=1pt,auto,node distance=1.5cm, thick,base node/.style={circle,draw,minimum size=20pt}, real node/.style={double,circle,draw,minimum size=20pt}]
\node[base node] (1) {$\lnot a$}; \node[base node] (2) [right of=1]{$\lnot b$}; \node[base node] (4) [right of=2] {$\lnot c$}; \node[base node] (5) [right of=4] {$\lnot e$}; \node[base node] (6) [above right of=5] {$d$}; \node[base node] (3) [below right of=5] {$\lnot d$}; \node[base node] (7) [below right of=6] {$\bot$}; \path[] (1) edge [] node {$3$} (2) edge [bend right] node {$4$} (3) (2) edge [] node {$5$} (4) edge [bend left=35] node {$1$} (6) (4) edge [] node {$2$} (5) edge [bend left=20] node {$1$} (6) (5) edge [] node {$4$} (3) (3) edge [] node {} (7) (6) edge [] node {} (7); \end{tikzpicture}
\begin{dpllCNFInput} \item $\{b, c, d\}$ \item $\{c, \lnot e\}$ \item $\{a, \lnot b\}$ \item $\{a, \lnot d, e\}$ \item $\{b, \lnot c\}$ \end{dpllCNFInput}
State the learned clause by making a resolution proof according to the given conflict graph and given clauses.
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