Questionnaire-2024/sat_solvers_dpll/0034_sol.tex

\hspace{-0.09cm}\scalebox{0.85}{
	\begin{dplltabular}{5}
		\dpllStep{1|2|3|4|5}
		\dpllDecL{0|0|0|1|1}
		\dpllAssi{ - |$b$|$b, \lnot e$|$b, \lnot e, \lnot a$|\makecell{$b, \lnot e, \lnot a, $ \\ $\lnot c$}}
		\dpllClause{1}{$a, \lnot c$}{$a, \lnot c$|$a, \lnot c$|$a, \lnot c$|$\lnot c$|\done}
		\dpllClause{2}{$b, c, e$}{$b, c, e$|\done|\done|\done|\done}
		\dpllClause{3}{$b, e$}{$b, e$|\done|\done|\done|\done}
		\dpllClause{4}{$\lnot a, c$}{$\lnot a, c$|$\lnot a, c$|$\lnot a, c$|\done|\done}
		\dpllClause{5}{$d, \lnot e$}{$d, \lnot e$|$d, \lnot e$|\done|\done|\done}
		\dpllClause{6}{$b, \lnot d$}{$b, \lnot d$|\done|\done|\done|\done}
		\dpllClause{7}{$\lnot d, \lnot e$}{$\lnot d, \lnot e$|$\lnot d, \lnot e$|\done|\done|\done}
		\dpllClause{8}{$a, c$}{$a, c$|$a, c$|$a, c$|$c$|\conflict}
		\dpllBCP{ - | - | - |$\lnot c$| - }
		\dpllPL{$b$|$\lnot e$| - | - | - }
		\dpllDeci{ - | - |$\lnot a$| - | - }
	\end{dplltabular}
}

Conflict in step 5\\
\scalebox{0.75}{

\begin{tikzpicture}[>=latex,line join=bevel,]
  \pgfsetlinewidth{1bp}
%%
\pgfsetcolor{black}
  % Edge: 1 -> 3
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  \definecolor{strokecol}{rgb}{0.0,0.0,0.0};
  \pgfsetstrokecolor{strokecol}
  \draw (54.0bp,50.5bp) node {$$1$$};
  % Edge: 1 -> 4
  \draw [->] (21.111bp,26.371bp) .. controls (26.482bp,23.828bp) and (33.482bp,20.828bp)  .. (40.0bp,19.0bp) .. controls (51.65bp,15.733bp) and (65.057bp,13.758bp)  .. (85.923bp,11.639bp);
  \draw (54.0bp,26.5bp) node {$$8$$};
  % Edge: 3 -> 2
  \draw [->] (107.67bp,47.438bp) .. controls (115.41bp,44.585bp) and (126.51bp,40.495bp)  .. (145.47bp,33.51bp);
  % Edge: 4 -> 2
  \draw [->] (107.67bp,14.223bp) .. controls (115.24bp,16.746bp) and (126.02bp,20.339bp)  .. (145.09bp,26.697bp);
  % Node: 1
\begin{scope}
  \definecolor{strokecol}{rgb}{0.0,0.0,0.0};
  \pgfsetstrokecolor{strokecol}
  \draw (11.0bp,31.0bp) ellipse (11.0bp and 11.0bp);
  \draw (11.0bp,31.0bp) node {$\lnot a$};
\end{scope}
  % Node: 3
\begin{scope}
  \definecolor{strokecol}{rgb}{0.0,0.0,0.0};
  \pgfsetstrokecolor{strokecol}
  \draw (97.0bp,51.0bp) ellipse (11.0bp and 11.0bp);
  \draw (97.0bp,51.0bp) node {$\lnot c$};
\end{scope}
  % Node: 4
\begin{scope}
  \definecolor{strokecol}{rgb}{0.0,0.0,0.0};
  \pgfsetstrokecolor{strokecol}
  \draw (97.0bp,11.0bp) ellipse (11.0bp and 11.0bp);
  \draw (97.0bp,11.0bp) node {$c$};
\end{scope}
  % Node: 2
\begin{scope}
  \definecolor{strokecol}{rgb}{0.0,0.0,0.0};
  \pgfsetstrokecolor{strokecol}
  \draw (156.0bp,30.0bp) ellipse (11.0bp and 11.0bp);
  \draw (156.0bp,30.0bp) node {$\bot$};
\end{scope}
%
\end{tikzpicture}


}
\begin{prooftree}
	\AxiomC{$1. \; a \lor \lnot c$}
	\AxiomC{$8. \; a \lor c$}
	\BinaryInfC{$a$}
\end{prooftree}

\hspace{-0.09cm}\scalebox{0.85}{
	\begin{dplltabular}{3}
		\dpllStep{6|7|8}
		\dpllDecL{0|0|0}
		\dpllAssi{$b, \lnot e$|$b, \lnot e, a$|\makecell{$b, \lnot e, a, $ \\ $c$}}
		\dpllClause{1}{$a, \lnot c$}{$a, \lnot c$|\done|\done}
		\dpllClause{2}{$b, c, e$}{\done|\done|\done}
		\dpllClause{3}{$b, e$}{\done|\done|\done}
		\dpllClause{4}{$\lnot a, c$}{$\lnot a, c$|$c$|\done}
		\dpllClause{5}{$d, \lnot e$}{\done|\done|\done}
		\dpllClause{6}{$b, \lnot d$}{\done|\done|\done}
		\dpllClause{7}{$\lnot d, \lnot e$}{\done|\done|\done}
		\dpllClause{8}{$a, c$}{$a, c$|\done|\done}
		\dpllClause{9}{$a$}{$a$|\done|\done}
		\dpllBCP{$a$|$c$| - }
		\dpllPL{ - | - | - }
		\dpllDeci{ - | - |SAT}
	\end{dplltabular}
}