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171 lines
4.1 KiB
171 lines
4.1 KiB
// Compute and print the n-th Fibonacci number.
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// We work with integers and real numbers.
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#include <cln/integer.h>
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#include <cln/real.h>
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// We do I/O.
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#include <cln/io.h>
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#include <cln/integer_io.h>
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// We use the timing functions.
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#include <cln/timing.h>
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using namespace std;
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using namespace cln;
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// F_n is defined through the recurrence relation
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// F_0 = 0, F_1 = 1, F_(n+2) = F_(n+1) + F_n.
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// The following addition formula holds:
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// F_(n+m) = F_(m-1) * F_n + F_m * F_(n+1) for m >= 1, n >= 0.
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// (Proof: For fixed m, the LHS and the RHS satisfy the same recurrence
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// w.r.t. n, and the initial values (n=0, n=1) agree. Hence all values agree.)
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// Replace m by m+1:
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// F_(n+m+1) = F_m * F_n + F_(m+1) * F_(n+1) for m >= 0, n >= 0
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// Now put in m = n, to get
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// F_(2n) = (F_(n+1)-F_n) * F_n + F_n * F_(n+1) = F_n * (2*F_(n+1) - F_n)
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// F_(2n+1) = F_n ^ 2 + F_(n+1) ^ 2
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// hence
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// F_(2n+2) = F_(n+1) * (2*F_n + F_(n+1))
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struct twofibs {
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cl_I u; // F_n
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cl_I v; // F_(n+1)
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// Constructor.
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twofibs (const cl_I& uu, const cl_I& vv) : u (uu), v (vv) {}
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};
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// Returns F_n and F_(n+1). Assume n>=0.
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static const twofibs fibonacci2 (int n)
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{
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if (n==0)
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return twofibs(0,1);
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int m = n/2; // floor(n/2)
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twofibs Fm = fibonacci2(m);
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// Since a squaring is cheaper than a multiplication, better use
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// three squarings instead of one multiplication and two squarings.
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cl_I u2 = square(Fm.u);
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cl_I v2 = square(Fm.v);
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if (n==2*m) {
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// n = 2*m
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cl_I uv2 = square(Fm.v - Fm.u);
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return twofibs(v2 - uv2, u2 + v2);
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} else {
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// n = 2*m+1
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cl_I uv2 = square(Fm.u + Fm.v);
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return twofibs(u2 + v2, uv2 - u2);
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}
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}
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// Returns just F_n. Assume n>=0.
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const cl_I fibonacci (int n)
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{
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if (n==0)
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return 0;
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int m = n/2; // floor(n/2)
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twofibs Fm = fibonacci2(m);
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if (n==2*m) {
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// n = 2*m
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// Here we don't use the squaring formula because
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// one multiplication is cheaper than two squarings.
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cl_I& u = Fm.u;
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cl_I& v = Fm.v;
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return u * ((v << 1) - u);
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} else {
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// n = 2*m+1
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cl_I u2 = square(Fm.u);
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cl_I v2 = square(Fm.v);
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return u2 + v2;
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}
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}
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// The next routine is a variation of the above. It is mathematically
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// equivalent but implemented in a non-recursive way.
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const cl_I fibonacci_compact (int n)
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{
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if (n==0)
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return 0;
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cl_I u = 0;
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cl_I v = 1;
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cl_I m = n/2; // floor(n/2)
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for (uintC bit=integer_length(m); bit>0; --bit) {
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// Since a squaring is cheaper than a multiplication, better use
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// three squarings instead of one multiplication and two squarings.
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cl_I u2 = square(u);
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cl_I v2 = square(v);
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if (logbitp(bit-1, m)) {
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v = square(u + v) - u2;
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u = u2 + v2;
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} else {
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u = v2 - square(v - u);
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v = u2 + v2;
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}
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}
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if (n==2*m)
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// Here we don't use the squaring formula because
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// one multiplication is cheaper than two squarings.
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return u * ((v << 1) - u);
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else
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return square(u) + square(v);
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}
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// Returns just F_n, computed as the nearest integer to
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// ((1+sqrt(5))/2)^n/sqrt(5). Assume n>=0.
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const cl_I fibonacci_slow (int n)
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{
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// Need a precision of ((1+sqrt(5))/2)^-n.
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float_format_t prec = float_format((int)(0.208987641*n+5));
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cl_R sqrt5 = sqrt(cl_float(5,prec));
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cl_R phi = (1+sqrt5)/2;
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return round1( expt(phi,n)/sqrt5 );
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}
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#ifndef TIMING
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int main (int argc, char* argv[])
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{
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if (argc != 2) {
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cerr << "Usage: fibonacci n" << endl;
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return(1);
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}
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int n = atoi(argv[1]);
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cout << "fib(" << n << ") = " << fibonacci(n) << endl;
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return(0);
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}
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#else // TIMING
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int main (int argc, char* argv[])
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{
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int repetitions = 100;
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if ((argc >= 3) && !strcmp(argv[1],"-r")) {
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repetitions = atoi(argv[2]);
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argc -= 2; argv += 2;
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}
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if (argc != 2) {
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cerr << "Usage: fibonacci n" << endl;
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return(1);
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}
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int n = atoi(argv[1]);
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{ CL_TIMING;
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cout << "fib(" << n << ") = ";
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for (int rep = repetitions-1; rep > 0; rep--)
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fibonacci(n);
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cout << fibonacci(n) << endl;
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}
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{ CL_TIMING;
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cout << "fib(" << n << ") = ";
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for (int rep = repetitions-1; rep > 0; rep--)
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fibonacci_compact(n);
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cout << fibonacci_compact(n) << endl;
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}
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{ CL_TIMING;
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cout << "fib(" << n << ") = ";
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for (int rep = repetitions-1; rep > 0; rep--)
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fibonacci_slow(n);
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cout << fibonacci_slow(n) << endl;
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}
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return(0);
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}
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#endif
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