The source code and dockerfile for the GSW2024 AI Lab.
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/* ZEBRA, Who Owns the Zebra? */
/* Written in GNU MathProg by Andrew Makhorin <mao@gnu.org> */
########################################################################
# The Zebra Puzzle is a well-known logic puzzle.
#
# It is often called "Einstein's Puzzle" or "Einstein's Riddle"
# because it is said to have been invented by Albert Einstein as a boy,
# with the common claim that Einstein said "only 2 percent of the
# world's population can solve". It is also sometimes attributed to
# Lewis Carroll. However, there is no known evidence for Einstein's or
# Carroll's authorship.
#
# There are several versions of this puzzle. The version below is
# quoted from the first known publication in Life International
# magazine on December 17, 1962.
#
# 1. There are five houses.
# 2. The Englishman lives in the red house.
# 3. The Spaniard owns the dog.
# 4. Coffee is drunk in the green house.
# 5. The Ukrainian drinks tea.
# 6. The green house is immediately to the right of the ivory house.
# 7. The Old Gold smoker owns snails.
# 8. Kools are smoked in the yellow house.
# 9. Milk is drunk in the middle house.
# 10. The Norwegian lives in the first house.
# 11. The man who smokes Chesterfields lives in the house next to the
# man with the fox.
# 12. Kools are smoked in the house next to the house where the horse
# is kept.
# 13. The Lucky Strike smoker drinks orange juice.
# 14. The Japanese smokes Parliaments.
# 15. The Norwegian lives next to the blue house.
#
# Now, who drinks water? Who owns the zebra?
#
# In the interest of clarity, it must be added that each of the five
# houses is painted a different color, and their inhabitants are of
# different national extractions, own different pets, drink different
# beverages and smoke different brands of American cigarettes. One
# other thing: In statement 6, right means your right.
#
# (From Wikipedia, the free encyclopedia.)
########################################################################
set HOUSE := { 1..5 };
set COLOR := { "blue", "green", "ivory", "red", "yellow" };
set NATIONALITY := { "Englishman", "Japanese", "Norwegian", "Spaniard",
"Ukranian" };
set DRINK := { "coffee", "milk", "orange_juice", "tea", "water" };
set SMOKE := { "Chesterfield", "Kools", "Lucky_Strike", "Old_Gold",
"Parliament" };
set PET := { "dog", "fox", "horse", "snails", "zebra" };
var color{HOUSE, COLOR}, binary;
c1{h in HOUSE}: sum{c in COLOR} color[h,c] = 1;
c2{c in COLOR}: sum{h in HOUSE} color[h,c] = 1;
var nationality{HOUSE, NATIONALITY}, binary;
n1{h in HOUSE}: sum{n in NATIONALITY} nationality[h,n] = 1;
n2{n in NATIONALITY}: sum{h in HOUSE} nationality[h,n] = 1;
var drink{HOUSE, DRINK}, binary;
d1{h in HOUSE}: sum{d in DRINK} drink[h,d] = 1;
d2{d in DRINK}: sum{h in HOUSE} drink[h,d] = 1;
var smoke{HOUSE, SMOKE}, binary;
s1{h in HOUSE}: sum{s in SMOKE} smoke[h,s] = 1;
s2{s in SMOKE}: sum{h in HOUSE} smoke[h,s] = 1;
var pet{HOUSE, PET}, binary;
p1{h in HOUSE}: sum{p in PET} pet[h,p] = 1;
p2{p in PET}: sum{h in HOUSE} pet[h,p] = 1;
/* the Englishman lives in the red house */
f2{h in HOUSE}: nationality[h,"Englishman"] = color[h,"red"];
/* the Spaniard owns the dog */
f3{h in HOUSE}: nationality[h,"Spaniard"] = pet[h,"dog"];
/* coffee is drunk in the green house */
f4{h in HOUSE}: drink[h,"coffee"] = color[h,"green"];
/* the Ukrainian drinks tea */
f5{h in HOUSE}: nationality[h,"Ukranian"] = drink[h,"tea"];
/* the green house is immediately to the right of the ivory house */
f6{h in HOUSE}:
color[h,"green"] = if h = 1 then 0 else color[h-1,"ivory"];
/* the Old Gold smoker owns snails */
f7{h in HOUSE}: smoke[h,"Old_Gold"] = pet[h,"snails"];
/* Kools are smoked in the yellow house */
f8{h in HOUSE}: smoke[h,"Kools"] = color[h,"yellow"];
/* milk is drunk in the middle house */
f9: drink[3,"milk"] = 1;
/* the Norwegian lives in the first house */
f10: nationality[1,"Norwegian"] = 1;
/* the man who smokes Chesterfields lives in the house next to the man
with the fox */
f11{h in HOUSE}:
(1 - smoke[h,"Chesterfield"]) +
(if h = 1 then 0 else pet[h-1,"fox"]) +
(if h = 5 then 0 else pet[h+1,"fox"]) >= 1;
/* Kools are smoked in the house next to the house where the horse is
kept */
f12{h in HOUSE}:
(1 - smoke[h,"Kools"]) +
(if h = 1 then 0 else pet[h-1,"horse"]) +
(if h = 5 then 0 else pet[h+1,"horse"]) >= 1;
/* the Lucky Strike smoker drinks orange juice */
f13{h in HOUSE}: smoke[h,"Lucky_Strike"] = drink[h,"orange_juice"];
/* the Japanese smokes Parliaments */
f14{h in HOUSE}: nationality[h,"Japanese"] = smoke[h,"Parliament"];
/* the Norwegian lives next to the blue house */
f15{h in HOUSE}:
(1 - nationality[h,"Norwegian"]) +
(if h = 1 then 0 else color[h-1,"blue"]) +
(if h = 5 then 0 else color[h+1,"blue"]) >= 1;
solve;
printf "\n";
printf "HOUSE COLOR NATIONALITY DRINK SMOKE PET\n";
for {h in HOUSE}
{ printf "%5d", h;
printf{c in COLOR: color[h,c]} " %-6s", c;
printf{n in NATIONALITY: nationality[h,n]} " %-11s", n;
printf{d in DRINK: drink[h,d]} " %-12s", d;
printf{s in SMOKE: smoke[h,s]} " %-12s", s;
printf{p in PET: pet[h,p]} " %-6s", p;
printf "\n";
}
printf "\n";
end;